SOLUTION: find the eccentricity of a hyperbola whose transverse and conjugate axes are equal in length?

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Question 1086201: find the eccentricity of a hyperbola whose transverse and conjugate axes are equal in length?
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
e = √(a2 +b2)/a
The fact that the transverse and conjugate axes are the same length means a and b are equal, and therefore the eccentricity becomes:
e = √(a2 + a2)/a and if we add the a in parenthesis we get:
e = √(2a2)/a