SOLUTION: the line UV has equation 5x-2y=7.the point U has coordinates (1,-1) and the point V has coordinates (3,r),find in general form ,the equation of the perpendicular bisector of UV

Algebra ->  Length-and-distance -> SOLUTION: the line UV has equation 5x-2y=7.the point U has coordinates (1,-1) and the point V has coordinates (3,r),find in general form ,the equation of the perpendicular bisector of UV      Log On


   



Question 1085416: the line UV has equation 5x-2y=7.the point U has coordinates (1,-1) and the point V has coordinates (3,r),find in general form ,the equation of the perpendicular bisector of UV
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Solving for y, UV has the equation +y+=+%285%2F2%29x+-+7%2F2+
Using the above, we can plug in x=3 in order to find r:
y = (5/2)(3) - 7/2
y = 15/2 - 7/2 = 8/2 = 4
So r=4, or equivalently, V is at (3,4).
Let the line MN be the perpendicular bisector of UV, and let M be the midpoint of UV.
Line MN has slope -2/5 (for y=mx+b, a line perpendicular Y=MX+B will always have slope M=-1/m).
So far for MN we have +y++=+-%282%2F5%29x+%2B+b+
We just need b.
To find b, we need M: M is at the midpoint of UV: ( +%283%2B1%29%2F2+ , +%284+%2B+%28-1%29%29+%2F+2+ ) or
( +2+ , 3%2F2+ )
Now plug in x & y and solve for b: +3%2F2+=+%28-2%2F5%29%282%29+%2B+b+ —> +b+=+3%2F2+%2B+4%2F5+=+15%2F10+%2B+8%2F10+=+23%2F10+

Ans: The perpendicular bisector of UV has equation +highlight_green%28y+=+%28-2%2F5%29x+%2B+23%2F10%29+