SOLUTION: Find the radius of a circle with center at (2,3),if a chord of lenght 8 is bisected at (-1,4) with solution Po plz

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Question 1085057: Find the radius of a circle with center at (2,3),if a chord of lenght 8 is bisected at (-1,4) with solution Po plz

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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Three segments make a right-angled triangle:

1)  the half of the chord;

2)  the perpendicular bisector from the center of the circle to the chord;  and

3)  the radius drawn from the center to the chord's endpoint.


The half of the chord has the length of 8%2F2 = 4 units.

The perpendicular bisector from the center of the circle to the chord has the length

    sqrt%28%282-%28-1%29%29%5E2+%2B+%283-4%29%5E2%29 = sqrt%283%5E2+%2B+%28-1%29%5E2%29 = sqrt%2810%29.

So, the right-angled triangle has two legs of 4 units and sqrt%2810%29 units long.


The radius of the circle is the hypotenuse of this triangle.

Hence, its length is sqrt%284%5E2+%2B+%28sqrt%2810%29%29%5E2%29 = sqrt%2816+%2B+10%29 = sqrt%2826%29.

Answer.  The radius of the circle is  sqrt%2826%29  units long.

Solved.