SOLUTION: locate the point which satisfies the given conditions. Equidistant from (3,8), (5,2) and (-3,-4)
Algebra
->
Length-and-distance
-> SOLUTION: locate the point which satisfies the given conditions. Equidistant from (3,8), (5,2) and (-3,-4)
Log On
Geometry: Length, distance, coordinates, metric length
Geometry
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Length-and-distance
Question 1045546
:
locate the point which satisfies the given conditions.
Equidistant from (3,8), (5,2) and (-3,-4)
Answer by
ikleyn(52780)
(
Show Source
):
You can
put this solution on YOUR website!
.
It is the center of the circle circumscribed about the triangle with the given vertices.
This point (the center) is the common intersection point of three straight lines that are the perpendicular bisectors of the sides of that triangle.
See the lesson
-
Perpendicular bisectors of a triangle sides are concurrent
in this site.
Also, be informed that you have this free of charge online textbook on Geometry
GEOMETRY - YOUR ONLINE TEXTBOOK
in this site.