SOLUTION: Segment JK is exactly 15 units long. Point J is located at (10,-8). Point K is located in quadrant 2 and is one unit above the x-axis. What are the coordinates of point K? (May som

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Question 1011570: Segment JK is exactly 15 units long. Point J is located at (10,-8). Point K is located in quadrant 2 and is one unit above the x-axis. What are the coordinates of point K? (May someone help me please and thank you)
* this is what I did before I confused myself:
After you add them together you have to find the square root, the square is the distance.(d stands for distance) I couldn't get the square root symbol I'm sorry.

d=15. 15=(x2-10)²+(y2-(-8))²
15=(x2-10)²+(9)²
15=(x2-10)²+(9)²
15=(x2-10)²+81
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
You have the given point J( 10, -8 ). The signs ( +, - )
tell you it is in the 4th quadrant.
The other point K looks like ( x, 1 )
------------------------------
If you used J as a center and made part of a circle with
radius = 15 in the 2nd quadrant, it crosses the line
and that is point K
----------------------------




I notice that so I can guess:

doesn't work -it's in the 1st quadrant
gives me signs ( -, + ), which is 2nd quadrant
so that works
Point K is ( -2, 1 )
------------------
check answer:





OK
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Segment JK is exactly 15 units long. Point J is located at (10,-8). Point K is located in quadrant 2 and is one unit above the x-axis. What are the coordinates of point K? (May someone help me please and thank you)
* this is what I did before I confused myself:
After you add them together you have to find the square root, the square is the distance.(d stands for distance) I couldn't get the square root symbol I'm sorry.

d=15. 15=(x2-10)²+(y2-(-8))²
15=(x2-10)²+(9)²
15=(x2-10)²+(9)²
15=(x2-10)²+81
You're on the right track, but you forgot to square the 15!

 <-------- This is what you have

 <------- This is what you should have



Continue to solve for  from here. You should get 2 values for , but one is positive and the

other is negative. You need the negative value since K is in the 2nd quadrant, where x is negative. 

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