SOLUTION: Show that the curvature of the polar curver=f(θ) is
κ=|2[f^' (θ)]^2-f(θ) f^'' (θ)+[f(θ)]^2 |/{[f^' (θ)]^2+[f(θ)]^2 }^(3/2) ’
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-> SOLUTION: Show that the curvature of the polar curver=f(θ) is
κ=|2[f^' (θ)]^2-f(θ) f^'' (θ)+[f(θ)]^2 |/{[f^' (θ)]^2+[f(θ)]^2 }^(3/2) ’
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Question 1011199: Show that the curvature of the polar curver=f(θ) is
κ=|2[f^' (θ)]^2-f(θ) f^'' (θ)+[f(θ)]^2 |/{[f^' (θ)]^2+[f(θ)]^2 }^(3/2) ’
unless f(θ_0 ) and f^' (θ_0 ) are both zero.