Tutors Answer Your Questions about Inverses (FREE)
Question 415948: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:
X^3 = 2Y+1
After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
Click here to see answer by stanbon(75887)  |
Question 415948: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:
X^3 = 2Y+1
After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
Click here to see answer by jim_thompson5910(35256) |
Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.
Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
Click here to see answer by stanbon(75887) |
Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.
Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
Click here to see answer by josmiceli(19441)  |
Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.
Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
Click here to see answer by Edwin McCravy(20054)  |
Question 424970: I am not sure if this equation was done right. Here it is
1/3+1/2
-------
5/9-1/3
Do I add the first equation to get that answer, subtract the second equation and take both answers and Divide them? Here is what I have on my sheet:
1/3+1/2 2/6+3/6 5/6
-------= -------= ---=5/6 * 9/2 = 5/6 * 27/6 = 45/12 ?
5/9-1/3 5/9-3/9 2/9
Is this any where close to being right?
Click here to see answer by Alan3354(69443)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295
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