Tutors Answer Your Questions about Inverses (FREE)
Question 589966: Decide whether or not the functions are inverses of each other.
1] f(x)= 4x+16 and g(x)= 1/4x-4
2] f(x)= sqrt(x+8), domain [-8, infinity); g(x)=x^2+8, domain (-infinity, infinity)
and last one:
Determine
i) the domain of the function,
ii) the range of the function,
iii) the domain of the inverse, and
iv) the range of the inverse.
f(x) = 2x + 1
I need help understanding these three questions :( Inverses was my least favorite in Algebra! If you could please help, would be greatly appreciated!
Click here to see answer by lwsshak3(11628)  |
Question 610007: Mary was asked to use inverse operations to solve the equation 5x-3=12. Which set of instructions shows the inverse operation? A. Add 3, then divide by 5. B. Multiply by 3, then subtract 5.
C. Subtract 3, then muliply by 5. D. Subtract 12, then divide by 5.
Click here to see answer by richard1234(7193)  |
Question 616249: Find the inverse of the following function. Find domain, range, and asymptotes of each function. f(x)=ln(x+1)+1
I tried to solve this but i got mixed up.
Here is what I had.
y=(x+1)+1
x=(y+1)+1
x-1=(y+1)-1
x-2=y
x-2=f^-1(x)
My teacher noted that I didn't add the ln to the equation upon solving.
Would it be x=ln(y+1)+1
Can someone please help me. Thanks
Also for the Domain, I'm guessing that I solve
x+1=0
x=-1 so the domain is (-1,inf)
I thought that there cannot be a domain for x<0.
So confused
Click here to see answer by jim_thompson5910(35256) |
Question 616717: I am having trouble with inverse operations in having to make x the subject. I have three questions in my workbook.
First question - make x the subject.
v= qx^2/t+p
I tried doing it but I am not sure if I have my working right. My end answer was that it is
x= sqrt(v-pt/q)
Any help would be appreciated thank you. This is the one that I understood the most. The other two absolutely blow my mind. Thanks :)
Click here to see answer by Alan3354(69443)  |
Question 623825: If f(x)= 2/(x-1), then f^-1(x)= ?
The way I tried solving this problem is by switching the x and y, and solving for y. I ended up with the answer f^-1(x)=(2+x)/x. Can you help me decide if this is the right answer, and let me know where I went wrong if this answer is wrong.
Click here to see answer by edjones(8007)  |
Question 623825: If f(x)= 2/(x-1), then f^-1(x)= ?
The way I tried solving this problem is by switching the x and y, and solving for y. I ended up with the answer f^-1(x)=(2+x)/x. Can you help me decide if this is the right answer, and let me know where I went wrong if this answer is wrong.
Click here to see answer by lwsshak3(11628) |
Question 632466: I am trying to find the inverse equation of F(x)= (2-x)/(5x)
I get x=(2-y)/(5y)
multiply 5y through to get (5yx)=(2-y)
I divide the whole equation by y to get (5x)=(2/y)-(y/y) (y/y equaling 1)
so now my equation is 5x=(2/y)-1then take over the one to get 5x+1=2/y
I am not sure how to get y on its own after that please help thank you
Click here to see answer by Alan3354(69443) |
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