SOLUTION: (a+b+c)(b+c-a)(c+a-b)(a+b-c)

Algebra ->  Inverses -> SOLUTION: (a+b+c)(b+c-a)(c+a-b)(a+b-c)       Log On


   

Question 970836: (a+b+c)(b+c-a)(c+a-b)(a+b-c)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

%28a%2Bb%2Bc%29%28b%2Bc-a%29%28c%2Ba-b%29%28a%2Bb-c%29+................multiply first two and then second two

%28-a%5E2%2Bb%5E2%2B2bc%2Bc%5E2%29%28a%5E2-b%5E2%2B2bc-c%5E2%29.....multiply these two and you will get

-a%5E4%2B2a%5E2+%2Ab%5E2%2B2a%5E2%2A+c%5E2-b%5E4%2B2b%5E2%2Ac%5E2-c%5E4