SOLUTION: y varies directly as x and inversely as the square of z. y=38 when x=32 and z=4. Find y when x=75 and z=5. y=

Algebra ->  Inverses -> SOLUTION: y varies directly as x and inversely as the square of z. y=38 when x=32 and z=4. Find y when x=75 and z=5. y=      Log On


   

Question 753789: y varies directly as x and inversely as the square of z. y=38 when x=32 and z=4. Find y when x=75 and z=5.
y=
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
y varies directly as x and inversely as the square of z
y = kx/z^2
(k is the constant of variation)
To find k use all the values given:-
y = kx/z^2
38 = k * 32/4^2
38 = k32/16
38 = 2k
k = 19
Formula => y = 19x/z^2
Solve:
y = 19x/z^2
y = 19*75/5^2
y = 1425/25
y = 57
Hope this helps
:-)