SOLUTION: 2(x-3)=5x+4 solve for x Here is what I have so far 2x-6=5x+4 +6 +6 2x=5x+10 -5x-5x -3x=10 <------ This is where I am stuck. What do I divide by?

Algebra ->  Inverses -> SOLUTION: 2(x-3)=5x+4 solve for x Here is what I have so far 2x-6=5x+4 +6 +6 2x=5x+10 -5x-5x -3x=10 <------ This is where I am stuck. What do I divide by?      Log On


   

Question 676850: 2(x-3)=5x+4 solve for x
Here is what I have so far
2x-6=5x+4
+6 +6
2x=5x+10
-5x-5x
-3x=10 <------ This is where I am stuck. What do I divide by?
Found 2 solutions by ReadingBoosters, littlebitlove:
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
2(x-3) = 5x +4
2x - 6 = 5x + 4
2x = 5x + 4 + 6
2x = 5x + 10
2x - 5x = 10
-3x = 10
...
Divide both sides by -3
highlight_green%28x+=+-10%2F3%29
...
If you have 2x = 5x + 10
then
2x - 2x = 5x + 10 - 2x
you get
0 = 3x + 10
subtract 10 from both sides
-10 = 3x
x = -10/3
.....................
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Answer by littlebitlove(26) About Me  (Show Source):
You can put this solution on YOUR website!
x=-10%2F3
You divide by the three it comes out with a fraction answer.