SOLUTION: I need help with my pre algerbra. We are learning about powers with negative exponents. My problem is:
b^8 * b^-6 * b^-9
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b^8 * b^-6 * b^-9
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Question 559166: I need help with my pre algerbra. We are learning about powers with negative exponents. My problem is:
b^8 * b^-6 * b^-9 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! b^8 * b^-6 * b^-9
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Add the exponents to get:
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b^(8-6-9)
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= b^(-7)
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= 1/b^(7)
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Cheers,
Stan H.
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