SOLUTION: The "floor" of a fraction is defined to be the largest integer which is not greater than that fraction. For instance, floor[10/3]=3. Evaluate: floor[floor(1000/7)/floor(71/2)].

Algebra ->  Inverses -> SOLUTION: The "floor" of a fraction is defined to be the largest integer which is not greater than that fraction. For instance, floor[10/3]=3. Evaluate: floor[floor(1000/7)/floor(71/2)].      Log On


   



Question 37388: The "floor" of a fraction is defined to be the largest integer which is not greater than that fraction. For instance, floor[10/3]=3. Evaluate:
floor[floor(1000/7)/floor(71/2)].

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From floor[floor(1000/7)/floor(71/2)], we work from the inside on out...
floor[floor(142.857)/floor(35.5)]=
floor(142/35) =
4