SOLUTION: which of the four functions below has an inverse which is the same as the function itself? A: f(x)=x-3 B: f(x)=1/2x C: f(x)=-x-2 D: f(x)= the square root of x+2

Algebra ->  Inverses -> SOLUTION: which of the four functions below has an inverse which is the same as the function itself? A: f(x)=x-3 B: f(x)=1/2x C: f(x)=-x-2 D: f(x)= the square root of x+2      Log On


   



Question 222993: which of the four functions below has an inverse which is the same as the function itself?
A: f(x)=x-3
B: f(x)=1/2x
C: f(x)=-x-2
D: f(x)= the square root of x+2

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
In all these equations, let y = f(x).

To find the inverse function, solve for x and then replace y with x and x with y.

alternatively you can replace y with x and x with y first, and then solve for y.

Either way you'll get the same answer.

selection A
y = x+3
Solve for x to get:
x = y-3
Replace x with y and y with x to get:
y = x-3 which is the inverse function of y = x+3

Selection B
y = x/2
Solve for x to get:
x = 2y
Replace x with y and y with x to get:
y = 2x which is the inverse function of y = x/2

Selection C
y = -x-2
Solve for x to get:
x = -y-2
Replace x with y and y with x to get:
y = -x-2 which is the inverse function of y = -x-2

Selection D
y= sqrt(x+2)
Solve for x as follows:
Square both sides to get:
y^2 = x+2
Subtract 2 from both sides to get:
y^2-2 = x which is the same as:
x = y^2-2
Replace x with y and y with x to get:
y = x^2-2 which is the inverse function of y = sqrt(x+2)

Selection C inverse equation is the same as the original equation.


graph of this equation is shown below:

graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-x-2%2Cx%29

The line y = -x-2 is a reflection about the line y = x which is a definition of inverse function.

Take any point (x,y) on the line y = -x-2 above the line y = x. The opposite point (y,x) on the line y = -x-2 below the line will be the same distance from the line y = x.

example:

let x = -2
then y = -(-2)-2 = 2-2 = 0
your coordinate point is (-2,0).

now let x = 0
then y = 0-2 = -2
your coordinate point is (0,-2)

the point (-2,0) is a reflection of the point (0,-2) about the line y = x

to prove that the distance between these points and the line y = x is the same, we need to find the point of intersection between these two lines.

the point of intersection with the line y = x would be (-1,-1) as shown on the graph.

The distance between the point (-2,0) and (-1,-1) is given by the equation:

sqrt%28%28-1-%28-2%29%29%5E2+%2B+%28-1-0%29%5E2%29 which equals sqrt%281%5E2%2B%28-1%29%5E2%29+=+sqrt%282%29

The distance between the point (0,-2) and (-1,-1) is given by the equation:

sqrt%28%28-1-0%29%5E2+%2B+%28-1-%28-2%29%29%5E2%29 which equals sqrt%28%28-1%29%5E2%2B1%5E2%29+=+sqrt%282%29

The point (-2,0) is a reflection of the point (0,-2) about the line y = x which is a requirement of inverse functions.

Selection C is your answer.