Since you posted this in the "inverses" section, I'll assume you want to find the inverse.
To do so, we will swap x and y, and then solve for y.
y = (3x)/(x+2)
x = (3y)/(y+2)
x(y+2) = 3y
xy+2x = 3y
2x = 3y-xy
2x = y(3-x)
(2x)/(3-x) = y
y = (2x)/(3-x)
Therefore, the inverse of y = (3x)/(x+2) is y = (2x)/(3-x)
y = (2x)/(3-x) is equivalent to y = (-2x)/(x-3) when we factor -1 out of the denominator.
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