Question 1099612: frank, sam, and louis went to lunch. sam's meal cost $.45 less than frank's. louis's meal cost twice as much as sam's. if the bill came $9.25, how much does each person owe?
Found 3 solutions by josgarithmetic, Boreal, stanbon:
Answer by josgarithmetic(39617)   (Show Source):
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! F=x
S=x-.45
L=2(x-.45)
sum is 9.25
x+x-.45+2x-.9=9.25
4x-1.35=9.25
4x=10.60
x=$2.65, Frank
x-.45=$2.20 Sam
2(x-.45)=$4.40 Louis
add to $9.25
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! frank, sam, and louis went to lunch. sam's meal cost $.45 less than frank's. louis's meal cost twice as much as sam's. if the bill came $9.25, how much does each person owe?
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Equations:
s = f-.45
L = 2s
s + L + f = 9.25
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Substitute for f and for L and solve for "s"::
s + 2s + s+0.45 = 9.25
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4s + 0.45 = 9.25
4s = 8.8
s = $2.20
L = 2s = $4.40
f = s + 0.45 = $2.65
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Cheers,
Stan H.
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