SOLUTION: If the 10th term of a geometric sequence is 32 times larger than the 5th term, then what is the common ratio of the sequence?

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Question 1091041: If the 10th term of a geometric sequence is 32 times larger than the 5th term, then what is the common ratio of the sequence?
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
a%5B10%5D = a%5B1%5D%2Ar%5E9,    (1)

a%5B5%5D = a%5B1%5D%2Ar%5E4.     (2)


=====>  a%5B10%5D%2Fa%5B5%5D = r%5E5 = 32  ====>  r = root%285%2C32%29 = 2.


Answer.  the common ratio of this geometric sequence is 2.

Solved.


There is a bunch of lessons on geometric progressions in this site
    - Geometric progressions
    - The proofs of the formulas for geometric progressions
    - Problems on geometric progressions
    - Word problems on geometric progressions
    - One characteristic property of geometric progressions
    - Solved problems on geometric progressions
    - Fresh, sweet and crispy problem on arithmetic and geometric progressions
    - Mathematical induction and geometric progressions
    - Mathematical induction for sequences other than arithmetic or geometric


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Geometric progressions".