Tutors Answer Your Questions about Inequalities (FREE)
Question 776554: I'm confused by the outcome I get from the problem 1/4|x-3|+2 <1 since < in the original equation is supposed to represent "and", yet my answer when graphed shows an "or" trend on my number line. When I solved it, I ended out with x <7 and x>-1. If you see anything I've done wrong, please correct me, and I thank you in advance for your input.
Click here to see answer by solver91311(24713)   |
Question 779090: Solve problem 68 on page 539 of Elementary and Intermediate Algebra, and make sure to study the given graph. For the purposes of the assignment, it would be helpful to copy the graph onto your own scratch paper.
Write a two to three page paper that is formatted in APA style and according to the Math Writing Guide. Format your math work as shown in the example and be concise in your reasoning. In the body of your essay, please make sure to include:
An answer to the three questions asked about given real-world situation.
An application of the given situation to the following two scenarios:
The Burbank Buy More store is going to make an order which will include at most 60 refrigerators. What is the maximum number of TVs which could also be delivered on the same 18-wheeler? Describe the restrictions this would add to the existing graph.
The next day, the Burbank Buy More decides they will have a television sale so they change their order to include at least 200 TVs. What is the maximum number of refrigerators which could also be delivered in the same truck? Describe the restrictions this would add to the original graph.
Click here to see answer by psbhowmick(878)  |
Question 779482: I need help with this inequality: |3x-2| ( < or equal to) 5
How would I graph this with my 2 answers? <----------->
I tried: 3x-2 <_ 5
3x<_ 7
X<_ 7/3
3x-2>_ -5
3x >_ -3
x >_ -1
This is from a test I got back, and I'm trying to figure out what I did wrong. I'm not sure if its the graphing or problem or both I messed up on. Thank you
Click here to see answer by mananth(16946)  |
Question 780019: Hi I need help with problem. I keep getting an impossible answer and i can't figure out what I'm doing wrong. This is the problem: The three sides of an equilateral triangle are increase by 20 cm, 30 cm, and 40 cm, respectively. The perimeter of the resulting triangle is between twice and three times the perimeter of the original triangle. What can you conclude about the length of a side of the original triangle?
Click here to see answer by stanbon(75887) |
Question 780019: Hi I need help with problem. I keep getting an impossible answer and i can't figure out what I'm doing wrong. This is the problem: The three sides of an equilateral triangle are increase by 20 cm, 30 cm, and 40 cm, respectively. The perimeter of the resulting triangle is between twice and three times the perimeter of the original triangle. What can you conclude about the length of a side of the original triangle?
Click here to see answer by MathLover1(20849)  |
Question 780035: Hi I don't understand how to set up this problem. During the first 20 mi of a 50 mi bicycle race, Roger's average speed was 16 mi/h. What must his average speed be during the remainder of the race if he is to finish the race in less than 2.5h?
Click here to see answer by lwsshak3(11628) |
Question 780035: Hi I don't understand how to set up this problem. During the first 20 mi of a 50 mi bicycle race, Roger's average speed was 16 mi/h. What must his average speed be during the remainder of the race if he is to finish the race in less than 2.5h?
Click here to see answer by stanbon(75887) |
Question 781151: How would I solve for this rational equation: x-3/3 is less than or equal to 2+(x/2)
I tried working it like this but I am not too sure it is right.
6*(x-3/3) is less than or equal to 6*(2+(x/2))
6x-18 is less than/equal to 12+6x
-18 is less than or equal to 12
Im just not sure if that's right. If you could help me that would be great because I am also struggling with another similar problem so I would appreciate it if you could help me out. Thanks
Click here to see answer by rothauserc(4718)  |
Question 782805: Consider Functions: Consider a square with side of length s, diagonal of length d, perimeter P, and area A.
a) Write A as a function of s.
b) Write s as a function of A.
c) Write s as a function of d.
d) Write d as a function of s.
e) Write P as a function of s.
f) Write s as a function of P.
g) Write A as a function of P.
h) Write d as a function of A.
Click here to see answer by oscargut(2103)  |
Question 783205: x +1 is greater than 0 and 3x - 4 is less than 0.
Solve the compound inequality and graph solution set.
for the first equation x + 1 is greater than 0 my answer is x is greater than -1, and my second equation my answer is x is less than 4/3.
I'm not sure I'm my answers are correct and if so I am not sure how to graph 4/3 on a straight number line?
Can I get help with my answers and how to draw them on the number line please?
Thank you for your time1
Click here to see answer by stanbon(75887) |
Question 783449: I cant get the solution correct: 3/5 (x-2)-1/4 (2x-7) ≤ 3
I tried mulitplying by the LCM 20 to get rid of the fractions and then this is how it goes from here:
12(x-2)-5(2x-7)≤ 60
12x-24-10x+35 ≤ 60
2x-11 ≤ 60
+11 +11
2x ≤ 71
2x/2 ≤ 71/2
x ≤ 71/2
Click here to see answer by fcabanski(1391) |
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