Tutors Answer Your Questions about Inequalities (FREE)
Question 30171: I am not good with inequalities so i need help with the following...
21-y=(-87)+2y
6-y=(-y)+2
4/3u-6=7/3u+8
7+6z=8z-13
12p=6-3p
5/6t+4=2-1/6t
3+2(k+1)=6+3k
6r+5=8(r+2)-2r
(-2)(2c-4=1/3(-12c+24)
u/0.3=4u+6.28
0.3x-15=0.2x-5
Click here to see answer by Bb(20) |
Question 30632: Question
State the valu of x in the following inequality
3/x-4<=2/x-2
Method i have tried.
Multiply both sides by the common denominator which is (x-4)(x-2) which gives you
3(x-2)<=2(x-4) therefore
3x-6<=2x-8
bring all the variable on one side leads me to
3x-2x<=-8+6
thefore
x<=-2
Click here to see answer by Earlsdon(6294) |
Question 30632: Question
State the valu of x in the following inequality
3/x-4<=2/x-2
Method i have tried.
Multiply both sides by the common denominator which is (x-4)(x-2) which gives you
3(x-2)<=2(x-4) therefore
3x-6<=2x-8
bring all the variable on one side leads me to
3x-2x<=-8+6
thefore
x<=-2
Click here to see answer by Cintchr(481) |
Question 28068: Please help me with this problem.
Six less than four times a number is twelve more then twice the number.Choose the equation to find the unknown number. then solve.
A. 6-4b=12+2b;b=-1
B. 4b-6=12+2b;b=-9
C. 4b-6=12+2b;b=9
Click here to see answer by Fermat(136)  |
Question 31488: I have been working on this Rational inequality since Saturday morning and am still miffed.
Problem: (x/x-2)>=5
I put the expression into standard from by (x)/(x-2)-5>=0
I used the LCD to factor and put into one single fraction for(x)-5(x-2)/(x-2)>=0.
Which gave me: (X-5x-10)/(x-2)>=0
After combining terms I had: (4x-10)/(x-2)>=0
Which I then set both numerator and demonitor to be solved for >=0 and arrivd at:
x>=10/4 or 5/2
and x-2=0 which is (+2-2)>=0 which is Undefined and not a solution since a zero in the denominnator can't be a solution.
So (2,5/2) became the boundary points to test for true and fasle statements.
This is where I get confused.
When I plugged this expression into my y= screen on my TI-83 Plus calculator it gave me a vertical asympotote where the solutions I came up with is located on the x-axis.
When I algebraically used test values for the three intervals of (-00,2) (2,5/2) (5/2,00) I was even more confused because, when I tested using (-2) for the first interval of (00,2) the result was (-4) a value that was not >=5 and for the next test interval of (2,5/2) and used (2.25) as a test value I still get a value less than 5.
And for the last test inteval of (5/2,00) I used (3) I still get a denominator (3-2) that is less than 5. So none of the solutions I came up with are true statements.
None of these test values would satisfy the inequality statement of being >= to 5.
So the only thing I could figure out was that the vertical asymptote must mean some sort of sign change that takes place, but whee in the solution process this takes place is a mystery to me, as I hunted til the cows did not come home trying to find this answer.
At this rate I will never get this take home quiz finished by Tuesday March 28th.
Your help in helping me with this task is greatly appreciated.
My God I have spent some 20 hours since Sat morning and its now nearly midnight Sunday.
Sincerely,
Robert S.
Click here to see answer by venugopalramana(3286) |
Question 31587: I am doing word problems. I am being asked to find the pair of integers with the greatest sum if the sum of two consecutive integers is less than 55. I have to write and equation and then solve it.
Click here to see answer by ikdeep(226)  |
Question 31657: a baker has 25 lbs of wheat and 5 lbs of sugar. To bake each loaf of bread, the baker needs to use 1.3 lbs of wheat and 0.5 lbs sugar. To bake each muffin, the baker needs 0.4 lbs of wheat and 0.16 lbs of sugar.
Set up the inequalities representing the baker's possible choices for baking the number of loaves of bread and muffins to use up his available resources(wheat and Sugar).
If each loaf of bread is sold for $2.50, and each muffin is sold for $1.15, define an equation to represent the baker's profit function. How many of each should he make for maximum profit?
Click here to see answer by Paul(988) |
Question 32056: (1/(x+2))+(2/(x-3))<=1
here is my work:
((x-3)+2(x+2)-((x+2)(x-3)))/((x+2)(x-3))<=0
you then simplify to get:
(-x^2 +2x +7)/((x+2)(x-3))<=0
but when you use the quadratic equation it is very ugly.
Thank you,
Alexus
Click here to see answer by Earlsdon(6294) |
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