SOLUTION: Im not sure if I chose the correct topic but could you please help me solve this equation? the original function is: f(x)=(2x)/(x-3). I have to find the inverse relation so switch

Algebra ->  Inequalities -> SOLUTION: Im not sure if I chose the correct topic but could you please help me solve this equation? the original function is: f(x)=(2x)/(x-3). I have to find the inverse relation so switch       Log On


   

Question 998599: Im not sure if I chose the correct topic but could you please help me solve this equation? the original function is: f(x)=(2x)/(x-3). I have to find the inverse relation so switch x and y. i have come up with the equation: x=(2y)/(y-3). i need help solving for y. so far i have xy-3x=2y
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=(2x)/(x-3)


y=(2x)/(x-3) ... replace f(x) with y


x=(2y)/(y-3) ... swap x and y; now solve for y


x(y-3)=2y ... Multiply both sides by y-3.


xy-3x=2y ... Distribute


xy=2y+3x ... Add 3x to both sides.


xy-2y=3x ... Subtract 2y from both sides.


y(x-2)=3x ... Factor


y=3x/(x-2) ... Divide both sides by x-2.


The inverse function is