SOLUTION: Solve for x in the inequality: -1 is less than (x+2)/(x-3) Any tips, tricks, advice for other inequality problems is greatly appreciated as well as help with this problem! Th

Algebra ->  Inequalities -> SOLUTION: Solve for x in the inequality: -1 is less than (x+2)/(x-3) Any tips, tricks, advice for other inequality problems is greatly appreciated as well as help with this problem! Th      Log On


   



Question 988807: Solve for x in the inequality:
-1 is less than (x+2)/(x-3)

Any tips, tricks, advice for other inequality problems is greatly appreciated as well as help with this problem! Thank you in advance!

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Solve for x in the inequality:
-1 is less than (x+2)/(x-3)

Any tips, tricks, advice for other inequality problems is greatly appreciated as well as help with this problem! Thank you in advance!
-+1+%3C+%28x+%2B+2%29%2F%28x+-+3%29, with x+%3C%3E+3 as this would make the denominator 0, and therefore, an UNDEFINED inequality 
-+1%28x+-+3%29+%3C+x+%2B+2 ----- Multiplying both sides by LCD, x - 3
-+x+%2B+3+%3C+x+%2B+2
-+x+%3C+x+%2B+2+-+3 -------- Subtracting 3 from both sides
-+x+%3C+x+-+1
-+x+-+x+%3C+-+1 --------- Subtracting x from both sides
-+2x+%3C+-+1
%28-+2x%29%2F%28-+2%29+%3E+%28-+1%29%2F%28-+2%29 -------- Inequality sign changes when dividing by a negative value
x+%3E+1%2F2
Now, we have the CRITICAL VALUES: system%28%281%2F2%29_and%2C3%29
This means that we will have THREE (3) TEST-INTERVALS to determine whether or not values
in the intervals SATISFY the ORIGINAL inequality: -+1+%3C+%28x+%2B+2%29%2F%28x+-+3%29. These TEST INTERVALS are:
1) x+%3C+1%2F2
2) 1%2F2+%3C+x+%3C+3, and
3) x+%3E+3
Testing x+%3C+1%2F2 with test value: x+=+0, -+1+%3C+%28x+%2B+2%29%2F%28x+-+3%29 becomes: -+1+%3C+%280+%2B+2%29%2F%280+-+3%29
-+1+%3C+2%2F%28-+3%29
-+1+%3C+-+2%2F3
As the above is TRUE, the test-interval: highlight_green%28x+%3C+1%2F2%29 IS a solution
Testing 1%2F2+%3C+x+%3C+3 with test value: x+=+1, -+1+%3C+%28x+%2B+2%29%2F%28x+-+3%29 becomes: -+1+%3C+%281+%2B+2%29%2F%281+-+3%29
-+1+%3C+3%2F%28-+2%29
-+1+%3C+-+1%261%2F2
As the above is FALSE, the test-interval: 1%2F2+%3C+x+%3C+3 IS NOT a solution
Testing x+%3E+3 with test value: x+=+4, -+1+%3C+%28x+%2B+2%29%2F%28x+-+3%29 becomes: -+1+%3C+%284+%2B+2%29%2F%284+-+3%29
-+1+%3C+6%2F1
-+1+%3C+6
As the above is TRUE, the test-interval: highlight_green%28x+%3E+3%29 IS a solution
In interval notation, this is: (- oo, ½) ᑌ (3, oo) , or (-+infinity%22%2C%221%2F2) ᑌ (3%22%2C%22infinity)