SOLUTION: This is driving me insane The sum of the lengths of any two sides of a triagle must be greater than the third side. If a triagle has one side that is 19 inches and a second

Algebra ->  Inequalities -> SOLUTION: This is driving me insane The sum of the lengths of any two sides of a triagle must be greater than the third side. If a triagle has one side that is 19 inches and a second       Log On


   

Question 96185: This is driving me insane
The sum of the lengths of any two sides of a triagle must be greater than the third side. If a triagle has one side that is 19 inches and a second side that is 2 inches less than twice the third side, what are the possible lengths for the second and third sides.
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of the lengths of any two sides of a triagle must be greater than the third side. If a triagle has one side that is 19 inches and a second side that is 2 inches less than twice the third side, what are the possible lengths for the second and third sides.
the question is asking for an answer of :
the second side is between_13 3/4_and 19 inches and the 3rd side is between
_5 1/4_ and _19______.
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One side = 19 inches
3rd side = x
2nd side = 3x-2
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EQUATION:
x + 3x-2 >19
4x > 21
x > 5 1/4 in
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Cheers,
Stan H.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X+(2X-2)>19
3X-2>19
3X>21
X>21/3
X>7 for the shorter unknown side.
THEN 2*7-2=14-2=12 or the other unknown side is >12