SOLUTION: I have to use the critical value method to solve the following rational inequality, and then I have to write the solution set in interval notation. However, I am a bit clueless wh

Algebra ->  Inequalities -> SOLUTION: I have to use the critical value method to solve the following rational inequality, and then I have to write the solution set in interval notation. However, I am a bit clueless wh      Log On


   



Question 950736: I have to use the critical value method to solve the following rational inequality, and then I have to write the solution set in interval notation.
However, I am a bit clueless what to do.
((x+3)(x-6))/x-4 < 0

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Break up the number line based on the critical values of your equation (that is, when it goes to zero or becomes undefined).
In this case,x=-3, x=4, and x=6.
This breaks the number line into 4 regions.
Region 1: x%3C-3
Region 2:-3%3Cx%3C4
Region 3:4%3Cx%3C6
Region 4:x%3E6
Now choose a point in each region (not an endpoint) and test the inequality.
If it's true, that region is part of the solution region.
If it's false, that region is not part of the solution region.
Region 1: x=-4
%28%28-4%2B3%29%28-4-6%29%29%2F%28-4-4%29%3C0
%28%28-1%29%28-10%29%29%2F%28-8%29%3C0
-10%2F8%3C0
True, part of the solution.
Region 2: x=0
%28%280%2B3%29%280-6%29%29%2F%280-4%29%3C0
%28-18%29%2F%28-4%29%3C0
9%2F2%3C0
False, not part of the solution.
Region 3: x=5
%28%285%2B3%29%285-6%29%29%2F%285-4%29%3C0
%28%288%29%28-1%29%29%2F%281%29%3C0
-8%3C0
True, part of the solution.
Region 4: x=7
%28%287%2B3%29%287-6%29%29%2F%287-4%29%3C0
%28%2810%29%281%29%29%2F%283%29%3C0
10%2F3%3C0
False, not part of the solution.
So then putting it all together,
Solution Region:(-infinity,-3)U(4,6)
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28%28x%2B3%29%28x-6%29%29%2F%28x-4%29%29