SOLUTION: Please help me solve this equation: {{{ 37/(3z+6)<= 1/3- 2z/(z+2) }}}
I am having trouble with multiplying the inequality by the LCD (least common denominator), which is 3z+6. I w
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-> SOLUTION: Please help me solve this equation: {{{ 37/(3z+6)<= 1/3- 2z/(z+2) }}}
I am having trouble with multiplying the inequality by the LCD (least common denominator), which is 3z+6. I w
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Question 946858: Please help me solve this equation:
I am having trouble with multiplying the inequality by the LCD (least common denominator), which is 3z+6. I wrote out the inequality like this:
The problem is I am not sure how to divide the denominators of the fractions into the least common denominator (3z+6). When I try to divide it, it turns into this:
The inequality above gives me an answer of but that is incorrect, so I'm confused. If you are able, could you please explain what I'm doing wrong? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 37/(3z+6)<= 1/3- 2z/(z+2)
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The LCD is 3(z+2)
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Multiplying thru by the LCD you get:
37 <= (z+2) - 6z
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37 <= -5z + 2
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5z <= 2-37
5z <= -35
z <= -7
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Cheers,
Stan H.
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