SOLUTION: can someone help me please Solve x^2 - 12 < 4x Solution (INTERVAL notation, no spaces)????
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Question 772186
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can someone help me please
Solve x^2 - 12 < 4x
Solution (INTERVAL notation, no spaces)????
Answer by
tommyt3rd(5050)
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x^2 - 12 < 4x
x^2-4x-12 < 0
(x-6)(x+2)<0
since this parabola has 2 real roots and opens upwards we know that between -2 and 6 it must be negative. So solution interval is (-2,6)