SOLUTION: I need to solve the inequality of x^2 > 5x-8. I am having troubles factoring it out. Thanks!

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Question 760578: I need to solve the inequality of x^2 > 5x-8.
I am having troubles factoring it out. Thanks!

Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%3E+5x-8
x%5E2-5x%2B8+%3E+5x-8-5x%2B8
x%5E2-5x%2B8%3E0

The quadratic expression is not factorable. You cannot use 8 and 1 whichever sign combination you use; and you cannot use 2 and 4, whichever sign combination you use. Just use general solution to quadratic formula to find the critical points (where the quadratic expression would be zero).

Critical points for inequality at:
%285%2B-+sqrt%2825-4%2A8%29%29%2F%282%29 which are complex with imaginary parts.
Same as %285%2B-+sqrt%28-7%29%29%2F2

The given inequality does NOT intersect the x-axis so has no real critical points. Just check any point for x. Either the inequality is true or it is false, for ALL values of x.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
I need to solve the inequality of x^2 > 5x-8.
I am having troubles factoring it out. Thanks!
***
x^2 > 5x-8
x^2-5x+8>0
equation is not factorable because there are no zeros or x-intercepts
by inspection, you can see that expression will always>0 for all values of x
solution: (-∞,∞)