SOLUTION: Solve the problem:
One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers.
Please show steps on this. Tha
Algebra ->
Inequalities
-> SOLUTION: Solve the problem:
One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers.
Please show steps on this. Tha
Log On
Question 760154: Solve the problem:
One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers.
Please show steps on this. Thank you :) Found 2 solutions by stanbon, MathLover1:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers.
-----
Equations:
o = s -1
2s = 4o - 20
--------
Substitute for "o" and solve for "s":
2s = 4(s-1) - 20
2s = 4s -24
2s = 24
second # = 12
------
Solve for "o":
o = s-1
o = 12-1
o = 11
==================
Cheers,
Stan H.
===================
You can put this solution on YOUR website!
if one number (let it be ) is less than a second number (let it be ), then
....eq.1
if twice the second number is less than times the first, then
....eq.2
solve the system:
....eq.1
....eq.2
_________________________
....eq.1...substitute in eq.2
....eq.2
now find ....eq.1
(