SOLUTION: Solve the equation and five the exact value log (3x) + log (x-2) = log (x-4)

Algebra ->  Inequalities -> SOLUTION: Solve the equation and five the exact value log (3x) + log (x-2) = log (x-4)       Log On


   

Question 759098: Solve the equation and five the exact value
log (3x) + log (x-2) = log (x-4)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

log+%283x%29+%2B+log+%28x-2%29+=+log+%28x-4%29+

log+%28%283x%29%28x-2%29%29+=+log+%28x-4%29+.......since lo same, we have

3x%28x-2%29+=+x-4+

3x%5E2-6x=+x-4+

3x%5E2-6x-x%2B4+=0

3x%5E2-7x%2B4+=0...write -7x as -3x-4x
3x%5E2-3x-4x%2B4+=0...group
%283x%5E2-3x%29-%284x-4%29+=0.....factor
3x%28x-1%29-4%28x-1%29+=0
%283x-4%29%28x-1%29+=0
solutions:
if 3x-4=0=>3x=4=>x=4%2F3=>
if x-1+=0=>x=1