SOLUTION: 1.) k+1/2 < k/4+2 When solved the inequality k was = to 0, so the variable was 0!

Algebra ->  Inequalities -> SOLUTION: 1.) k+1/2 < k/4+2 When solved the inequality k was = to 0, so the variable was 0!      Log On


   

Question 75680This question is from textbook Algebra 1
: 1.) k+1/2 < k/4+2 When solved the inequality k was = to 0, so the variable was 0! This question is from textbook Algebra 1

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
k%2B1%2F2+%3C+k%2F4%2B2
4%28k%2B1%2Fcross%282%29%29+%3C+cross%284%29%28k%2Fcross%284%29%2B2%29 Multiply both sides by 4 (this is the LCD). This clears any denominators
4k%2B2%3Ck%2B8
3k%2B2%3C8 Subtract k from both sides
3k%3C6 Subtract 2 from both sides
k%3C2 Divide both sides by 3. This is your solution set
If you want the answer in interval notation it is:

I'm not sure where you got an answer of 0 from, so double check your steps or tell me if I translated something wrong.


Check:
To test our solution set, pick any number that is less than 2 and plug it into k
1%2B1%2F2+%3C+1%2F4%2B2 Let k=1
2%2F2%2B1%2F2+%3C+1%2F4%2B8%2F4
3%2F2+%3C+9%2F4
3%2F2+%3C+9%2F4
1.5%3C2.25 works.


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
k+(1/2) <(k/4)+2
Multiply both sides by 4 to get:
4k+2 < k+8
3k<6
k<2
=================
Cheers,
Stan H.