SOLUTION: 16+logbase3(a^4)>0

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Question 756055: 16+logbase3(a^4)>0
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
logbase3(a^4)>-16
4*logbase3(a)>-16
logbase3(a)>-4
3^logbase3(a)>3^-4
a>1/81