SOLUTION: the cost.in dollars.Of publishing x books is C(x)=40.000 + 20x +0.0001x^2 .How many books can be published $250.000?

Algebra ->  Inequalities -> SOLUTION: the cost.in dollars.Of publishing x books is C(x)=40.000 + 20x +0.0001x^2 .How many books can be published $250.000?      Log On


   

Question 733810: the cost.in dollars.Of publishing x books is C(x)=40.000 + 20x +0.0001x^2 .How many books can be published $250.000?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given:
C%28x%29=40000+%2B+20x+%2B0.0001x%5E2+
$C%28x%29=250000
find x

250000=40000+%2B+20x+%2B0.0001x%5E2+
250000-40000+=+20x+%2B0.0001x%5E2+

210000+=+20x+%2B0.0001x%5E2+

++0.0001x%5E2%2B20x-210000=0+

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-20+%2B-+sqrt%28+20%5E2-4%2A+0.0001%2A%28-210000%29+%29%29%2F%282%2A0.0001%29+

x+=+%28-20+%2B-+sqrt%28+400%2B84+%29%29%2F0.0002+
x+=+%28-20+%2B-+sqrt%28+484+%29%29%2F0.0002+


x+=+%28-20+%2B-+22%29%2F0.0002+

solution:
we need only positive solution since we are looking for number of books

x+=+%28-20+%2B+22%29%2F0.0002+

x+=+2%2F0.0002+

x+=+10000+