SOLUTION: 6(2y-2<3y+4(2y+1)-17 is the problem and here is what I did which may be wrong because I'm stuck now. I need some help. I distributed and got 12y-12<3y+8y+4-17. Then I'm lost from t

Algebra ->  Inequalities -> SOLUTION: 6(2y-2<3y+4(2y+1)-17 is the problem and here is what I did which may be wrong because I'm stuck now. I need some help. I distributed and got 12y-12<3y+8y+4-17. Then I'm lost from t      Log On


   

Question 68865: 6(2y-2<3y+4(2y+1)-17 is the problem and here is what I did which may be wrong because I'm stuck now. I need some help. I distributed and got 12y-12<3y+8y+4-17. Then I'm lost from there.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Treat this problem as if it had an equal sign. You need to get the y's by themselves, so you should simplify the right side first
12y-12%3C3y%2B8y%2B4-17
12y-12%3C11y-13
the subtract 11y from both sides
12y-11y-12%3Ccross%2811y%29-cross%2811y%29-13
y-12%3C-13
then add 12 to both sides
y%2Bcross%28-12%29%2Bcross%2812%29%3C-13%2B12
y%3C-1