SOLUTION: Evaluate the expression. - 5/6 * ( - 9/10 ) divided by 17/20 Please work very very fast! Happy Holidays!~!~!~!~!

Algebra ->  Inequalities -> SOLUTION: Evaluate the expression. - 5/6 * ( - 9/10 ) divided by 17/20 Please work very very fast! Happy Holidays!~!~!~!~!      Log On


   

Question 65851This question is from textbook Pre-Algebra
: Evaluate the expression.
- 5/6 * ( - 9/10 ) divided by 17/20






Please work very very fast! Happy Holidays!~!~!~!~! This question is from textbook Pre-Algebra

Found 2 solutions by funmath, Edwin McCravy:
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Evaluate the expression.
- 5/6 * ( - 9/10 ) divided by 17/20
First flip the 17/20 and multiply by the reciprocal.
%28-5%2F6%29%2A%28-9%2F10%29%2A%2820%2F17%29
Now notice that there are an even number of - signs, so your answer whil be positive. Also do some cancelling before you multiply, because life is too short to simplify after the fact.
%28-5%2F%283%2A2%29%29%2A%28%28-3%2A3%29%2F%2810%29%29%2A%28%282%2A10%29%2F17%29

%28-5%2F1%29%2A%28-3%2F1%29%2A%281%2F17%29 Multiply the numerators and denominators that are reamining.
highlight%2815%2F17%29
Happy Calculating!!!

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Evaluate the expression.
- 5/6 * ( - 9/10 ) divided by 17/20 

%28-5%2F6%29%28-9%2F10%29÷%2817%2F20%29

We do the multiplication first because it's
the first of the highest level of operation
that appears. It is a negative multiplied by
a negative, so we know the answer will be
positive so we just write
%285%2F6%29%289%2F10%29÷%2817%2F20%29

We can cancel the 5 into the 10 and write 1
where we had 5 and 2 where we had 10:

%281%2F6%29%289%2F2%29÷%2817%2F20%29

We can also cancel the 6 and the 9 by 
dividing both by 3 and putting 3 where
we had 9 and 2 where we had 6

%281%2F2%29%283%2F2%29÷%2817%2F20%29
 
Now multiply numerators 1·3 = 3 and 
denominators 2·2 = 4 and we have

%283%2F4%29÷%2817%2F20%29

Invert the second fraction and change
division to multiplication:

%283%2F4%29×%2820%2F17%29

We can now cancel the 20 and the 4 
by dividing both by 4 and putting 5
where we had 20 and 1 where we had 4.

%283%2F1%29×%285%2F17%29

Finally we multiply numerators
3·5 getting 15, and multiply
denominators 1·17 = 17, and so
the final answer is

15%2F17

Edwin