SOLUTION: Using set builder notation solve and show work x-9=>7(x+2) (=> is my sign for greater than or equal too) Thank you

Algebra ->  Inequalities -> SOLUTION: Using set builder notation solve and show work x-9=>7(x+2) (=> is my sign for greater than or equal too) Thank you       Log On


   



Question 634509: Using set builder notation solve and show work
x-9=>7(x+2)
(=> is my sign for greater than or equal too) Thank you

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note: it should be >= and not =>, but that's ok



x-9%3E=7%28x%2B2%29 Start with the given inequality.


x-9%3E=7x%2B14 Distribute.


x%3E=7x%2B14%2B9 Add 9 to both sides.


x-7x%3E=14%2B9 Subtract 7x from both sides.


-6x%3E=14%2B9 Combine like terms on the left side.


-6x%3E=23 Combine like terms on the right side.


x%3C=%2823%29%2F%28-6%29 Divide both sides by -6 to isolate x. note: Remember, the inequality sign flips when we divide both sides by a negative number.


x%3C=-23%2F6 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x%3C=-23%2F6


The answer in set-builder notation is