SOLUTION: I graphed this inequalitity but it does not look right... y>x^2+x-6 y<x+3 can someone help?

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Question 63288: I graphed this inequalitity but it does not look right...
y>x^2+x-6
y can someone help?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y>x^2+x-6
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graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cx%5E2%2Bx-6%29
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This is the graph of y=x^2+x-6
You want y>x^2+x-6 so you want the
area that is above the curve. For
each x-value you want all the points
that have y-values above the y-value
of the curve point.
The parabola forms a cup. Shade the
inside of the cup; that is the graph
you want.
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Cheers,
Stan H.