SOLUTION: Q1. -2 &#8804; x + 3 &#8804; 0 Q2. x + 4 < 0 or 6x > -12 Q3. x &#8804; 0 or x &#8805; -3 Q4. &#8540; x + 1 &#8804; 0 or -2x < -4

Algebra ->  Inequalities -> SOLUTION: Q1. -2 &#8804; x + 3 &#8804; 0 Q2. x + 4 < 0 or 6x > -12 Q3. x &#8804; 0 or x &#8805; -3 Q4. &#8540; x + 1 &#8804; 0 or -2x < -4       Log On


   

Question 62727: Q1. -2 ≤ x + 3 ≤ 0
Q2. x + 4 < 0 or 6x > -12
Q3. x ≤ 0 or x ≥ -3
Q4. ⅜ x + 1 ≤ 0 or -2x < -4
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Q1. -2 ≤ x + 3 ≤ 0
Subtract 3 along the line to get:
-5<=x<=-3
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Q2. x + 4 < 0 or 6x > -12
x<-4 or x>-2
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Q3. x ≤ 0 or x ≥ -3
True
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Q4. ⅜ x + 1 ≤ 0 or -2x < -4
(3/8)x<=-1 or x>2
x<=-8/3 or x>2
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Cheers,
Stan H.