SOLUTION: Hi, I know this question is odd because it isn't a cube equation and it isn't a quadratic equation, but it goes like this: {{{ x^3+6x=10 }}} PLEASE help me! I really don't know w

Algebra ->  Inequalities -> SOLUTION: Hi, I know this question is odd because it isn't a cube equation and it isn't a quadratic equation, but it goes like this: {{{ x^3+6x=10 }}} PLEASE help me! I really don't know w      Log On


   



Question 604536: Hi, I know this question is odd because it isn't a cube equation and it isn't a quadratic equation, but it goes like this: +x%5E3%2B6x=10+
PLEASE help me! I really don't know what to do! Thank you so much.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E3%2B6x=10+
It's a cubic equation. It has no x^2 term but the x^3 makes it a cubic.
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+x%5E3%2B6x-10+=+0
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x = {q + [q^2 + (r-p^2)^3]^1/2}^1/3 + {q - [q^2 + (r-p^2)^3]^1/2}^1/3 + p
where
p = -b/(3a), q = p^3 + (bc-3ad)/(6a^2), r = c/(3a)
------------
a = 1, b = 0, c = 6, d = -10
-------------
p = 0
q = 5
r = 2
---------
x = {5 + [25 + 8]^1/2}^1/3 + {5 - [25 + 8]^1/2}^1/3
= root%283%2C%285+%2B+sqrt%2833%29%29%29+%2B+root%283%2C%285+-+sqrt%2833%29%29%29
x =~ 1.300270977 the only real number solution