SOLUTION: the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
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-> SOLUTION: the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
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Question 57475This question is from textbook
: the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
x+x+2+x+4<100
3x+6<100
-6 -6
3x<94
dived by 3 both sides
equals
x<31 and one third This question is from textbook
You can put this solution on YOUR website! the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
x+x+2+x+4<100
3x+6<100
-6 -6
3x<94
dived by 3 both sides
equals
x<31 and one third
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You've done everything right so far. You just need to finalize your thoughts and calculations.
Because you need them to be integers:
x<31 (without the one third)
The first odd integer: X=31
The second odd integer: x+2=33
The third odd integer: x+4=35
:
Check:
31+33+35=99
If you went with 33+35+37=105 So you're right:-)
Happy Calculating!!!
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