SOLUTION: Solve the inequality and graph the solution set on a real number line. (1/x+1) > (2/x-1) Here is what I was trying: (1/x+1) > (2/x-1) -(2/x-1) > 0 ___________ ______ (

Algebra ->  Inequalities -> SOLUTION: Solve the inequality and graph the solution set on a real number line. (1/x+1) > (2/x-1) Here is what I was trying: (1/x+1) > (2/x-1) -(2/x-1) > 0 ___________ ______ (      Log On


   

Question 531952: Solve the inequality and graph the solution set on a real number line.
(1/x+1) > (2/x-1)
Here is what I was trying:
(1/x+1) > (2/x-1)
-(2/x-1) > 0
__________________
(1/x+1)-(2/x-1) > 0
(1(x-1)/((x+1)(x-1))-(2(x+1)/(x+1)(x-1))>0
________________________________________
(x-1-2x-2)/((x+1)(x-1))>0
_______________________
(-x-3)/(x+1)(x-1)>0
________________________
Set numerator equal to 0
-x-3=0

x=3
________________________
Set denominator equal to 0
x+1=0 x=-1
x-1=0 x=1
__________________________
Then I got stuck! I don't even know if I was doing the first part right.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Not sure how to read this without the use of parentheses!
Is it %281%2Fx%29%2B1+%3E+%282%2Fx%29-1
or 1%2F%28x%2B1%29+%3E+2%2F%28x-1%29?
I'll assume the second one.
1%2F%28x%2B1%29+%3E+2%2F%28x-1%29 Simplify.
1%2A%28x-1%29%2F%28x%2B1%29%28x-1%29+%3E+2%2A%28x%2B1%29%2F%28x%2B1%29%28x-1%29 Multiply both sides by (x+1)(x-1) to clear the denominators.
x%2B1+%3E+2%28x-1%29
x%2B1+%3E+2x-2 Subtract x from both sides.
1+%3E+x-2 Add 2 to both sides.
3+%3E+x or
x+%3C+3
Your answer of x = 3 cannot be correct as you are dealing with inequalities.