SOLUTION: moving company a charges $80 plus $55 an hour to move households across town. moving company b charges $75 an hour for cross town moves. For what lengths of time in moving company

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Question 485285: moving company a charges $80 plus $55 an hour to move households across town. moving company b charges $75 an hour for cross town moves. For what lengths of time in moving company b more expensive than moving company a? Write an inequality and solve for time t.
total charge of company a in t hours
total charge of company b in t hours
write the following inequality to determine t
total charge of company a in t hours>total charge of company b in t hours
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Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
total charge of company a in t hours is %2880%2B55t%29
total charge of company b in t hours is 75t
For what lengths of time in moving company b more expensive than moving company a? , So total charge of company a in t hours 80%2B55t%3C75t
55t-75t%3C-80
-20t%3C-80divide by (-20), when we divide inequality by negative number the sign of inequality are changed
t%3E80%2F20
t%3E4
If working time is t%3E4hours, then moving company b more expensive than moving company a