SOLUTION: find solution set of (3x+2)^100(5-x)^99/(2x-7)^101<=0

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Question 462450: find solution set of (3x+2)^100(5-x)^99/(2x-7)^101<=0
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
%283x%2B2%29%5E100%285-x%29%5E99%2F%282x-7%29%5E101%3C=0
The inequality is in standard form already (i.e., one side of the inequality is equal to zero).
The critical numbers are:
-2/3, 7/2, and 5.
(-infinity, -2/3): %283x%2B2%29%5E100%285-x%29%5E99%2F%282x-7%29%5E101+%3C+0. (Choose test number x = -1.)
( -2/3, 7/2): %283x%2B2%29%5E100%285-x%29%5E99%2F%282x-7%29%5E101+%3C+0. (Choose test number x = 0).
(7/2, 5): %283x%2B2%29%5E100%285-x%29%5E99%2F%282x-7%29%5E101+%3E+0. (Choose test number x = 4.)

(5, infinity): %283x%2B2%29%5E100%285-x%29%5E99%2F%282x-7%29%5E101+%3C+0. (Choose test number x = 6.)
The critical numbers -2/3 and 5 also satisfy the inequality, but not 7/2. Hence the solution set is the union
(-infinity, 7/2) U [5, infinity).