You can put this solution on YOUR website! First up, let S = (1+a)(1 + b)(1 + c)(1 + d) = 1+c + d + cd + b + bc + bd + bcd + a + ac + ad + acd + ab + abc + abd + abcd. (This expression has 16 terms.)
By the AM-GM inequality, we have
, since abcd = 1.
Hence