SOLUTION: Can anyone help me with the following? Find all four corner points of the feasible region of the following system of inequalities: x + 4y < 8 x - y < 3 x > 0 y > 0 Tha

Algebra ->  Inequalities -> SOLUTION: Can anyone help me with the following? Find all four corner points of the feasible region of the following system of inequalities: x + 4y < 8 x - y < 3 x > 0 y > 0 Tha      Log On


   

Question 426831: Can anyone help me with the following?
Find all four corner points of the feasible region of the following system of inequalities:
x + 4y < 8
x - y < 3
x > 0
y > 0
Thank you!! :)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find all four corner points of the feasible region of the following system of inequalities:
x + 4y < 8
Graph y = (-1/4)x+2 as a dashed line.
y-intercept: (0,2)
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x - y < 3
Graph y = x-3 as a dashed line.
x-intercept: (3,0)
Intercept with y = (-1/4)x+2 is (4,1)
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x > 0
Graph the y-axis as a dashed line.
----------------------
y > 0
Graph the x-axis as a dashed line.
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Intercept of the two axis (0,0)
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graph%28400%2C300%2C-10%2C10%2C-3%2C3%2C%28-1%2F4%29x%2B2%2Cx-3%29
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Cheers,
Stan H.
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