Question 405390: How do you solve for the inequality 6x-(2x+3)is greater than or equal to 4x-5?
Answer by IWork4Dessert(60)   (Show Source):
You can put this solution on YOUR website! 6x-(2x+3)≥4x-5
The first thing you have to do is look at PEMDAS, order of operations.
P: parentheses
E: exponents
M: multiplication
D: division
A: addition
S: subtraction
You see that parentheses come first, but since you have no like terms within your parentheses, you can't simplify them yet. So you move on to multiplication next.
If you look closely at the problem, you can multiply in it.
-(2x+3)
Whenever there's a negative sign outside of parentheses, you distribute it inside the parentheses.
-2x-3
6x-2x-3≥4x-5
Now you want to isolate your variable, x, on one side of the equation. For example's sake, let's get it to the left side.
Combine your like terms on the left side.
4x-3≥4x-5
Now here's the tricky part. Normally you would subtract the "x" on the right side from the "x" on the left side, but they're both the same. This means that they cancel out.
So this would be a no-solution problem. That's your answer.
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Hope this helps!
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