SOLUTION: The instructions on this one say to solve each of the quadratic equations by factoring and applying the property ab=0 if and only if a=0 or b=0 The problem I need help with is:

Algebra ->  Inequalities -> SOLUTION: The instructions on this one say to solve each of the quadratic equations by factoring and applying the property ab=0 if and only if a=0 or b=0 The problem I need help with is:       Log On


   



Question 345301: The instructions on this one say to solve each of the quadratic equations by factoring and applying the property ab=0 if and only if a=0 or b=0 The problem I need help with is:
4x^2+29x+30=0

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll help you factor. I'll let you take over after that.




Looking at the expression 4x%5E2%2B29x%2B30, we can see that the first coefficient is 4, the second coefficient is 29, and the last term is 30.


Now multiply the first coefficient 4 by the last term 30 to get %284%29%2830%29=120.


Now the question is: what two whole numbers multiply to 120 (the previous product) and add to the second coefficient 29?


To find these two numbers, we need to list all of the factors of 120 (the previous product).


Factors of 120:
1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120
-1,-2,-3,-4,-5,-6,-8,-10,-12,-15,-20,-24,-30,-40,-60,-120


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 120.
1*120 = 120
2*60 = 120
3*40 = 120
4*30 = 120
5*24 = 120
6*20 = 120
8*15 = 120
10*12 = 120
(-1)*(-120) = 120
(-2)*(-60) = 120
(-3)*(-40) = 120
(-4)*(-30) = 120
(-5)*(-24) = 120
(-6)*(-20) = 120
(-8)*(-15) = 120
(-10)*(-12) = 120

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 29:


First NumberSecond NumberSum
11201+120=121
2602+60=62
3403+40=43
4304+30=34
5245+24=29
6206+20=26
8158+15=23
101210+12=22
-1-120-1+(-120)=-121
-2-60-2+(-60)=-62
-3-40-3+(-40)=-43
-4-30-4+(-30)=-34
-5-24-5+(-24)=-29
-6-20-6+(-20)=-26
-8-15-8+(-15)=-23
-10-12-10+(-12)=-22



From the table, we can see that the two numbers 5 and 24 add to 29 (the middle coefficient).


So the two numbers 5 and 24 both multiply to 120 and add to 29


Now replace the middle term 29x with 5x%2B24x. Remember, 5 and 24 add to 29. So this shows us that 5x%2B24x=29x.


4x%5E2%2Bhighlight%285x%2B24x%29%2B30 Replace the second term 29x with 5x%2B24x.


%284x%5E2%2B5x%29%2B%2824x%2B30%29 Group the terms into two pairs.


x%284x%2B5%29%2B%2824x%2B30%29 Factor out the GCF x from the first group.


x%284x%2B5%29%2B6%284x%2B5%29 Factor out 6 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B6%29%284x%2B5%29 Combine like terms. Or factor out the common term 4x%2B5


So 4x%5E2%2B29x%2B30 factors to %28x%2B6%29%284x%2B5%29.


In other words, 4x%5E2%2B29x%2B30=%28x%2B6%29%284x%2B5%29.


Note: you can check the answer by expanding %28x%2B6%29%284x%2B5%29 to get 4x%5E2%2B29x%2B30 or by graphing the original expression and the answer (the two graphs should be identical).


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider making a donation at my tutoring website. Thank you.

Jim