SOLUTION: A rectangle has length ( x + 11) in width 2x in . the perimeter of the rectangle is at least 47 inches and at most 52 inches .find the greatest value of x that satisfies the cond
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Question 310939: A rectangle has length ( x + 11) in width 2x in . the perimeter of the rectangle is at least 47 inches and at most 52 inches .find the greatest value of x that satisfies the condition Answer by palanisamy(496) (Show Source):
You can put this solution on YOUR website! Given,
A rectangle has length ( x + 11) in width 2x in
Its perimeter = 2[x+11+2x]=6x+22
Given,
the perimeter of the rectangle is at least 47 inches and at most 52 inches
47< 6x+22< 52
47-22< 6x< 52-22
25< 6x< 30
25/6< x < 30/6
25/6
So the maximum value of x is 5
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