If a>b, then which one of the following must be true:
a) a-b < 1 b) ab > b c) a + 1 > b d) a + b > 3b
Try (a)
It can't be a-b < 1 because 3 > 1 yet 3-1 is 2 which is not less than 1
Try (b)
It can't be ab > b because 1 > 0 yet 1*0 is 0 which is not greater than 0
Try (d)
It can't be a + b > 3b because 3 > 2 yet 3+2 is 5 which is not greater
than 3*2 which is 6
So it must be (c). a + 1 > b for if a is larger than b, adding 1 to the
larger one, a, can only make it EVEN MORE LARGER than b.
(Is it correct to say "MORE LARGER"? Must be! :)
Edwin