SOLUTION: Suppose you have two squares, one of which is larger than the other. Suppose further that the side of the larger square is seven times as long as the side of the smaller square.

Algebra ->  Inequalities -> SOLUTION: Suppose you have two squares, one of which is larger than the other. Suppose further that the side of the larger square is seven times as long as the side of the smaller square.       Log On


   

Question 202050: Suppose you have two squares, one of which is larger than the other. Suppose further that the side of the larger square is seven times as long as the side of the smaller square.
If the length of the side of the smaller square is x, find the area of each square.
Find the number of smaller squares it will take to cover the larger square.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Side length of smaller square: s=x

Area of smaller square: A=x%5E2



Side length of larger square: s=7x

Area of larger square: A=%287x%29%5E2=49x%5E2



Now simply divide the area of the larger square into the area of the smaller square to find out how many smaller squares will fit in the larger square:

%2849x%5E2%29%2F%28x%5E2%29=%2849%2Across%28x%5E2%29%29%2F%28cross%28x%5E2%29%29=49


So 49 smaller squares can fit into the larger square.