SOLUTION: x^2 + y^2 <= 1 (x-1)^2 + y^2 <= 1 Is it possible to find x and y?

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Question 174571: x^2 + y^2 <= 1
(x-1)^2 + y^2 <= 1
Is it possible to find x and y?
Found 2 solutions by ankor@dixie-net.com, Fombitz:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2 <= 1
(x-1)^2 + y^2 <= 1
---------------------subtraction eliminates y^2
x^2 - (x-1)^2 <= 0
Foil
x^2 - (x^2 - 2x + 1) =< 0
Remove brackets
x^2 - x^2 + 2x - 1 =< 0
2x - 1 =< 0
2x =< + 1
x =< .5
:
Find y using x^2 + y^2 =< 1
.5^2 + y^2 =< 1
.25 + y^2 =< 1
y^2 =< 1 -.25
y^2 =< .75
y =< +/-sqrt%28.75%29
y =< .866
y => -.866

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First graph,
x%5E2+%2B+y%5E2+%3C=+1
That's a circle centered at (0,0) with a radius of 1.
Including all of the interior points.

Next graph,
%28x-1%29%5E2+%2B+y%5E2+%3C=+1
That's a circle centered at (1,0) with a radius of 1.
Including all of the interior points.

When you put those two together,
the region that satisfies both equations is the football shaped section in between the two circles.