SOLUTION: The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? Write an inequality to model the
Algebra ->
Inequalities
-> SOLUTION: The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? Write an inequality to model the
Log On
Question 170214: The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? Write an inequality to model the problem.
You can put this solution on YOUR website! Since the perimeter of any rectangle is:
width + width + length + length
2(width) + 2(length)
2(width + length)
.
Let w = width of rectangle
then because "length of a rectangle is three times its width"
3w = length of rectangle
.
2(width + length) <= 112
plugging in our variables above:
2(w + 3w) <= 112
2(4w) <= 112
8w <= 112
w <= 112/8
w <= 14 centimeters (width)
.
Solution: greatest possible width is 14 centimeters
